The potential energy of a pair of nucleons is minimum when they are separated by about : A). $0.8 \times 10^{-15}\text{ m}$ B). $0.8 \times 10^{-10}\text{ m}$ C). $2.0 \times 10^{-13}\text{ m}$ D). $2.0 \times 10^{-14}\text{ m}$

The correct answer is $0.8 \times 10^{-15}\text{ m}$. **SOLUTION** The potential energy between a pair of nucleons is strongly repulsive at extremely short distances and becomes attractive at larger distances. The potential energy reaches its minimum (most stable bound state) at a separation distance of roughly **$0.8\text{ fm}$** ($0.8 \times 10^{-15}\text{ m}$).

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