Physics > modern-physics > Nuclei

When a neutron collides with ${}^{235}_{92}\text{U}$, the nucleus gives ${}^{140}_{54}\text{Xe}$ and ${}^{94}_{38}\text{Sr}$ as fission products and two neutrons are ejected. Calculate the mass defect and the energy released (in MeV) in the process.

Given: $m\!\left({}^{235}_{92}\text{U}\right) = 235\cdot04393 \text{ u}, \quad m\!\left({}^{140}_{54}\text{Xe}\right) = 139\cdot92164 \text{ u}$ $m\!\left({}^{94}_{38}\text{Sr}\right) = 93\cdot91536 \text{ u}, \quad m\!\left({}^{1}_{0}\text{n}\right) = 1\cdot00866 \text{ u}$ $1 \text{ u} = 931 \text{ MeV}/c^2$