Phenols are dramatically different from aliphatic alcohols despite both having the group. Direct attachment of to a benzene ring causes resonance delocalisation of the oxygen lone pair into the ring, making phenols far more acidic than alcohols, far more reactive toward electrophilic aromatic substitution (EAS), and incapable of simple dehydration or oxidation reactions that alcohols undergo. Ethers, by contrast, are remarkably unreactive — the oxygen lone pairs are tied up, and with no bond there is no acidity and no H-bonding. Yet both phenols and ethers are essential in JEE/NEET chemistry, with phenols particularly rich in distinct reactions — Kolbe, Reimer-Tiemann, Fries rearrangement, coupling — each a direct product of the activating group on the ring.
1. Phenols — Preparation
Method 1 — From Diazonium Salt (most important for JEE)
Method 2 — From Chlorobenzene (Dow's Process)
Requires harsh conditions — aromatic C–Cl bond is very strong (resonance). The intermediate sodium phenoxide is acidified to release phenol.
Method 3 — Cumene Process (Industrial)
Benzene + propene → cumene (isopropylbenzene) → cumene hydroperoxide → phenol + acetone.
This is the main industrial route; also produces acetone as a valuable byproduct.
Method 4 — Fusion of Sodium Benzene Sulphonate
2. Physical Properties of Phenol
- Colourless crystalline solid, B.P. = 182°C; melts at 41°C.
- Slightly soluble in water (6 g per 100 mL at 25°C) — hydrogen bonding with water. Miscible above 66°C.
- Has a distinctive medicinal/carbolic smell; corrosive to skin.
- B.P. higher than toluene (same mol. mass) due to H-bonding, but lower than benzyl alcohol (same H-bonding but more flexible chain).
3. Acidic Character of Phenol
Phenol is a much stronger acid than alcohols (), but weaker than carboxylic acids ().
Why is phenol more acidic than alcohols? The phenoxide ion () is stabilised by resonance — the negative charge is delocalised into the aromatic ring (ortho and para positions). No such stabilisation exists for alkoxide ions.
Effect of substituents on phenol acidity
- Electron-withdrawing groups (NO₂, CN, Cl at ortho/para) — stabilise phenoxide → increase acidity
- Electron-donating groups (CH₃, OCH₃ at ortho/para) — destabilise phenoxide → decrease acidity
- p-nitrophenol > m-nitrophenol > phenol > p-methylphenol (cresol)
4. Chemical Reactions of Phenol
A. Reaction with NaOH (confirms acidity)
Unlike alcohols, phenol reacts with cold dilute NaOH (not just Na metal). It does NOT react with (too weak a base) — this distinguishes phenol from carboxylic acids (which DO react with ).
B. Kolbe's Reaction (carboxylation)
Electrophilic attacks the electron-rich ortho/para positions of phenoxide. Product: salicylic acid (aspirin precursor).
C. Reimer-Tiemann Reaction (formylation)
Electrophile = dichlorocarbene () generated from . Attacks ortho position. Product is an aldehyde (hence "formylation").
D. Electrophilic Aromatic Substitution (EAS)
The group is a powerful ortho/para director and ring activator (lone pair donation into ring). Phenol reacts under much milder conditions than benzene:
- Bromination: — no catalyst needed, aqueous bromine water, all three ortho/para positions react.
- Nitration: — mild conditions (no need for mixed acid).
E. Fries Rearrangement
e.g., Phenyl acetate o-hydroxyacetophenone + p-hydroxyacetophenone. Higher temp favours ortho product; lower temp favours para product.
F. Azo Coupling (with diazonium salt)
Electrophilic aromatic substitution at the para position of phenol (activated ring). Azo coupling requires an electron-rich ring (phenol, aniline).
G. FeCl₃ Test for Phenol
Phenol gives a violet/purple colour with neutral solution (forms ferric phenoxide complex). This is a specific test to distinguish phenol from aliphatic alcohols.
5. Ethers — Preparation and Properties
Preparation — Williamson Synthesis (most important)
mechanism — must use primary alkyl halide (secondary/tertiary halides give elimination instead). The alkoxide is the nucleophile.
To make unsymmetrical ethers: choose the larger group as (from alkoxide) and the smaller primary group as (from halide). Example: to make methylphenyl ether (anisole): .
Physical Properties of Ethers
- Much lower boiling points than isomeric alcohols — no bond, no H-bonding between ether molecules.
- Slightly soluble in water — oxygen can accept H-bonds from water (H-bond acceptor but not donor).
- Good solvents for organic reactions (especially diethyl ether) — dissolve many organic compounds, unreactive.
- Highly flammable (low boiling point, high vapour pressure).
Chemical Properties of Ethers
Ethers are generally unreactive — the C–O–C linkage is stable. Key reactions:
- Cleavage by HI or HBr (strong acid): (or with excess HI). HI > HBr > HCl in reactivity for ether cleavage. The less sterically hindered carbon is attacked by .
- Formation of peroxides (danger!): Diethyl ether forms explosive hydroperoxides on prolonged exposure to air and light. Always check before distilling old ether.
- Anisole (methoxybenzene): The group directs EAS to ortho and para positions (ring activation). Anisole undergoes Friedel-Crafts, nitration, halogenation under milder conditions than benzene.
Comparison: Phenol vs Ether (for anisole)
| Property | Phenol () | Anisole () |
| Acidic character | Yes () | None ( absent) |
| FeCl₃ test | Violet colour | No colour |
| React with NaOH | Yes | No |
| Kolbe/Reimer-Tiemann | Yes (phenoxide needed) | No |
| EAS activation | Strong (o/p director) | Strong (o/p director) |
Practice Questions
Q1 (JEE Main / NEET): Phenol reacts with bromine water to give a white precipitate. Name the product and give the number of bromine atoms in one molecule of the product.
Explanation:
Product: 2,4,6-tribromophenol. Number of atoms = 3.
The group is a strongly activating, ortho/para-directing group. In an aqueous medium (bromine water), phenol ionises to form the phenoxide ion, which activates the ring even further. Consequently, all three available ortho/para positions (two ortho, one para) are immediately brominated. No Lewis acid catalyst (like ) is needed because the aromatic ring is highly nucleophilic.
Q2 (NEET): Which of the following will give a positive test?
A) Ethanol
B) Diethyl ether
C) Phenol
D) Acetic acid
Answer: C) Phenol.
Explanation: Phenol gives a characteristic violet/purple colouration with a neutral iron(III) chloride () solution due to the formation of a coloured coordination complex (a ferric phenoxide complex). Ethanol, diethyl ether, and acetic acid do not possess the enolic or phenolic required to give this test.
Q3 (JEE Main): How will you synthesise anisole () from phenol using the Williamson ether synthesis?
Explanation:
Step 1: Convert phenol to the more nucleophilic sodium phenoxide by treating it with sodium hydroxide:
Step 2: React the sodium phenoxide with methyl iodide (a primary alkyl halide):
Note: The alkyl halide () must be primary (or methyl) so that the substitution pathway dominates over elimination. You cannot use an aryl halide (like bromobenzene) because the bond has partial double-bond character and resists attack.
Q4 (Board): Explain why phenol is a stronger acid than ethanol.
Explanation:
When phenol loses a proton, it forms the phenoxide ion (). The negative charge on the oxygen atom is highly stabilised by resonance delocalisation into the aromatic ring (the lone pairs on the oxygen are conjugated with the -system, spreading the electron density over the ortho and para carbons). This resonance stabilisation makes phenoxide a highly stable, weak conjugate base.
In contrast, when ethanol loses a proton to form the ethoxide ion (), there is no resonance stabilisation. The negative charge remains entirely localised on the oxygen atom, and the alkyl group actually destabilises it further via the +I (inductive) effect. A less stable conjugate base means a weaker acid. Therefore, phenol () is a much stronger acid than ethanol ().
Q5 (JEE Main): What product is formed when anisole () is cleaved with concentrated ?
Explanation:
For aryl alkyl ethers like anisole, nucleophilic cleavage by always dictates that the halide ion () attacks the alkyl carbon via an mechanism. It cannot attack the aryl carbon because the aryl bond is unusually strong due to resonance (partial double-bond character) and hybridisation.
The products are strictly phenol + iodomethane.