CBSE 2025, Compartment, Set 4

Question

Identify the correct possible output(s) of the following code segment. Also write the minimum and the maximum possible values of the variable `b`.

```python
import random
s = "War and Peace"
a = len(s) // 2
for i in range (4):
    b = random.randrange(i, a)
    print(s[b], end="+")
``` A). n+p+d+a+ B). w+r+n+n+ C). e+r+w+a+ D). a+p+e+r+

Edvaya · Accepted Answer

The correct answer is w+r+n+n+. **Step-by-step execution:** 1. The string is `s = "War and Peace"`. Its length is 13. 2. `a = len(s) // 2 = 13 // 2 = 6`. 3. The loop runs for `i = 0, 1, 2, 3`. - When `i = 0`: `b` can be any random integer from 0 to 5. Available characters: `s[0]` to `s[5]` (`"W", "a", "r", " ", "a", "n"`). - When `i = 1`: `b` from 1 to 5. - When `i = 2`: `b` from 2 to 5. - When `i = 3`: `b` from 3 to 5. **Analyzing Options:** (A) `n+p+d+a+`: `p` is at index 8, but max `b` is 5. (Incorrect) (B) `w+r+n+n+`: (Assuming case insensitivity typo in option, W is at 0, r at 2, n at 5, n at 5). All are within bounds (0-5, 1-5, 2-5, 3-5). (Correct) (C) `e+r+w+a+`: `e` is at index 9. (Incorrect) (D) `a+p+e+r+`: `p` is at index 8. (Incorrect) - **Correct Output:** (B) - **Minimum possible value of `b`:** 0 (occurs when `i=0`). - **Maximum possible value of `b`:** 5 (since `randrange(stop)` doesn't include the stop value 6).

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Computer Science > Computational Thinking And Programming 2 > Functions

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