CBSE 2025, Set 3

Question

A capacitor and an inductor are connected in series across an ac source of voltage of variable frequency. The frequency is increased continuously. The nature of the circuit before and after the resonance will be : A). inductive only B). capacitive only C). capacitive and inductive respectively D). inductive and capacitive respectively

Edvaya · Accepted Answer

The correct answer is capacitive and inductive respectively. In a series L-C circuit, the total reactance is $X = X_L - X_C$.

Where inductive reactance $X_L = 2\pi f L$ and capacitive reactance $X_C = \frac{1}{2\pi f C}$.

* **Before resonance (low frequency):** $X_C > X_L$. The circuit is dominated by the capacitor and behaves capacitively.
* **At resonance:** $X_L = X_C$. The reactances cancel out.
* **After resonance (high frequency):** $X_L > X_C$. The circuit is dominated by the inductor and behaves inductively.

Thus, the nature is **capacitive and inductive respectively**.

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Physics > Magnetism Induction And Alternating Current > Alternating Current

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