CBSE 2014, Set 1

Question

The following data were obtained during the first order thermal decomposition of $SO_2Cl_2$ at a constant volume:
$$SO_2Cl_2 (g) \rightarrow SO_2 (g) + Cl_2 (g)$$

| Experiment | Time/$s^{-1}$ | Total pressure/atm |
| :---: | :---: | :---: |
| 1 | 0 | 0.4 |
| 2 | 100 | 0.7 |

Calculate the rate constant.
(Given: log 4 = 0.6021, log 2 = 0.3010)

Edvaya · Accepted Answer

The correct answer is Subjective. **SOLUTION** The thermal decomposition of $SO_2Cl_2$ at a constant volume is represented by following reaction. | | $SO_2Cl_2 (g)$ | $ightarrow$ | $SO_2 (g)$ | $+$ | $Cl_2 (g)$ | | :--- | :---: | :---: | :---: | :---: | :---: | | At t = 0 | $P_0$ | | 0 | | 0 | | At t = t | $P_0 - p$ | | p | | p | After time t, total pressure is given as, $$P_t = (P_0 - p) + p + p$$ $$P_t = P_0 + p$$ or $$p = P_t - P_0$$ $$	herefore P_0 - p = P_0 - (P_t - P_0) = 2P_0 - P_t$$ For a first order reaction the rate constant is given as: ![Rate Constant formula](https://www.edvaya.com/img/17.png) Substituting the value of $p$ ![Substitute p](https://www.edvaya.com/img/18.png) At t = 100s ![Calculation](https://www.edvaya.com/img/19.png) Therefore, the rate constant is $1.386 	imes 10^{-2} 	ext{ s}^{-1}$

Edvaya Target

Edvaya Aspire

Take a Free Mock Test

Target Subjects

Aspire Subjects

Subject Mastery

Chemistry > Physical Chemistry > Chemical Kinetics

Keep Practicing

Current Question

Community Stats

Track Your Progress

Edvaya Target

We Value Your Privacy