CBSE 2024, Set 1

Question

A step-up transformer has 200 and 3000 turns in its primary and secondary coils respectively. The input voltage given to the primary coil is $90	ext{ V}$. Calculate: (1) The output voltage across the secondary coil (2) The current in the primary coil if the current in the secondary coil is $2.0	ext{ A}$.

Edvaya · Accepted Answer

The correct answer is Subjective. **SOLUTION** Given parameters: * Primary turns, $N_p = 200$ * Secondary turns, $N_s = 3000$ * Primary voltage, $V_p = 90	ext{ V}$ * Secondary current, $I_s = 2.0	ext{ A}$ **(1) Output voltage across the secondary coil ($V_s$):** Using the transformer turn ratio formula: $$\frac{V_s}{V_p} = \frac{N_s}{N_p}$$ $$V_s = V_p 	imes \frac{N_s}{N_p}$$ $$V_s = 90 	imes \frac{3000}{200}$$ $$V_s = 90 	imes 15 = 1350	ext{ V}$$ **(2) Current in the primary coil ($I_p$):** Assuming an ideal transformer, input power equals output power: $$\frac{I_p}{I_s} = \frac{N_s}{N_p}$$ $$I_p = I_s 	imes \frac{N_s}{N_p}$$ $$I_p = 2.0 	imes \frac{3000}{200}$$ $$I_p = 2.0 	imes 15 = 30	ext{ A}$$

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Physics > Magnetism Induction And Alternating Current > Alternating Current

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