CBSE 2024, Set 1

Question

You know that there are twenty different types of naturally occurring amino acids and four different types of bases in the DNA. A combination of 3 such bases code for a specific amino acid. If instead there are 96 different amino acids and 12 different bases in the DNA, then the minimum number of combination of bases required to form a codon is: A). 6 B). 8 C). 2 D). 4

Edvaya · Accepted Answer

The correct answer is 2. **SOLUTION** Let's calculate the possible combinations based on the hypothetical scenario: * We have **12** different bases. * We need to code for **96** different amino acids. If a codon consists of $n$ bases, the total number of possible combinations is given by $	ext{Bases}^n$. * If $n = 1$ (1 base per codon): $12^1 = 12$ combinations (Not enough for 96 amino acids). * If $n = 2$ (2 bases per codon): $12^2 = 144$ combinations. Since $144$ is greater than $96$, a minimum sequence of **2 bases** is sufficient to code for all 96 amino acids.

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Biology > Reproduction And Genetics > Molecular Basis Of Inheritance

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